(3x-y)(2x^2+4xy-5)=

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Solution for (3x-y)(2x^2+4xy-5)= equation: 


Simplifying
(3x + -1y)(2x2 + 4xy + -5) = 0

Reorder the terms:
(3x + -1y)(-5 + 4xy + 2x2) = 0

Multiply (3x + -1y) * (-5 + 4xy + 2x2)
(3x * (-5 + 4xy + 2x2) + -1y * (-5 + 4xy + 2x2)) = 0
((-5 * 3x + 4xy * 3x + 2x2 * 3x) + -1y * (-5 + 4xy + 2x2)) = 0
((-15x + 12x2y + 6x3) + -1y * (-5 + 4xy + 2x2)) = 0
(-15x + 12x2y + 6x3 + (-5 * -1y + 4xy * -1y + 2x2 * -1y)) = 0

Reorder the terms:
(-15x + 12x2y + 6x3 + (-4xy2 + -2x2y + 5y)) = 0
(-15x + 12x2y + 6x3 + (-4xy2 + -2x2y + 5y)) = 0

Reorder the terms:
(-15x + -4xy2 + 12x2y + -2x2y + 6x3 + 5y) = 0

Combine like terms: 12x2y + -2x2y = 10x2y
(-15x + -4xy2 + 10x2y + 6x3 + 5y) = 0

Solving
-15x + -4xy2 + 10x2y + 6x3 + 5y = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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